如何在Linux中编译后以这样的方式编译c / cpp代码以提供经过预处理的汇编文件和目标文件？

Question

if source file is source.cpp then compiler output should have source.i source.s source.o in my directory not only .o file.

where

1. preprocessed = source.i
2. assembly = source.s
3. object = source.o

i know first two files are being created but later on they got deleted only .o file is shown so that linker can link object file but i want to see those two files also.

for linux any flag or something?.

Answer 1

According to the gcc man pages

-save-temps -save-temps=cwd Store the usual "temporary" intermediate files permanently; place them in the current directory and name them based on the source file. Thus, compiling foo.c with -c -save-temps would produce files foo.i and foo.s, as well as foo.o. This creates a preprocessed foo.i output file even though the compiler now normally uses an integrated preprocessor.

so you should compile your code like this

g++ -save-temps source.cpp

Answer 2

You can create individual file for each stage of compiler.

Preprocessor : g++ -E file.cpp -o file.i

Translator : g++ -S file.i -o file.s

Assembler : g++ -c file.s -o file.o

linker : g++ file.o -o file