[英]How to create a dictionary with columns given as keys and values
Ok so I am given two columns 好吧,我得到两列
A S
A T
A Z
B F
B G
B P
B U
C D
C P
C R
D M
E H
F S
H U
The 1st column is a list of points, and the second column is the list of the neighbors of the points. 第一列是点的列表,第二列是点的邻居的列表。 I would like to make it a dictionary so that {A:'S','T','Z', B:'F','G','P' etc} and so on.
我想将其设为字典,以便{A:'S','T','Z',B:'F','G','P'等}等。
What I have tried doing is this, given that the text file is the two columns. 鉴于文本文件是两列,因此我尝试这样做。
edges = open('romEdges.txt')
edgeslist = edges.read().split()
edgeskeys = edgeslist[::2]
edgesvalues = edgeslist[1::2]
dictionary = {}
for items in edgeskeys:
dictionary[items]=[]
dictionary = OrderedDict(sorted(dictionary.items(), key=lambda t: t[0]))
for items in edgeskeys:
if edgeskeys[items]==dictionary[items]:
print()
print(dictionary)
I have tried making 2 lists, 1 of keys and 1 of values, and tried comparing them to the dictionary, etc, and I just can't get it right! 我尝试制作2个列表,1个键和1个值,并尝试将它们与字典进行比较,等等,但我做对了!
THERE HAS to be a simple way. 有一种简单的方法。
Please help. 请帮忙。
Why not just plain simple line-by-line processing? 为什么不仅仅进行简单的逐行处理呢?
f = open('romEdges.txt')
dic = {}
for l in f:
k, v = l.split()
if k in dic:
dic[k].extend(v)
else:
dic[k] = [v]
f.close()
print dic
Output from your input: 输入的输出:
{'A': ['S', 'T', 'Z'], 'C': ['D', 'P', 'R'], 'B': ['F', 'G', 'P', 'U'], 'E': ['H'], 'D': ['M'], 'F': ['S'], 'H': ['U']}
For People who just want to create a simple dictionary from colums without recurring keyvalues this should work: 对于只想从列创建简单字典而又不重复键值的用户,这应该可行:
edges = open('romEdges.txt')
dict = {line[:1]:line[1:] for line in edges}
print dict
edges.close()
now you have possibly some whitespaces or Backspaces in the values, then you can replace() that with empty strings: 现在您的值中可能包含一些空格或Backspace,那么您可以使用空字符串replace():
edges = open('romEdges.txt')
dict = {line[:1]:line[1:].split()[0] for line in edges}
print dict
edges.close()
if you have multiple colums, and you want to have a list out of the following colums to that keyvalue: 如果您有多个列,并且想要从以下列中找到该键值的列表:
edges = open('romEdges.txt')
dict = {line[:1]:line[1:].split() for line in edges}
print dict
edges.close()
f = open('romEdges.txt')
dic = {}
for l in f : 对于f中的 l :
k, v = l.split('\t')
dic.setdefault(k,[])
if k in dic.keys():
dic[k].extend([v.strip()])
else:
dic[k] =[v]
f.close()
print dic
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