从两个列表中删除重复项

Question

I have written some code in python to remove duplicate items from lists. I have two separate lists that look like:

lhsNet = ['p', 'p', 'p', 'p', '(2)H', 'p', '(2)H', 'p', '(3)He', '(3)He']

rhsNet = ['(2)H', 'e+', 'nu_e', '(2)H', 'e+', 'nu_e', '(3)He', 'gamma', '(3)He', 'gamma', '(4)He', 'p', 'p']

Here is the code:

for x in lhsNet:
    for z in rhsNet:
        if x == z:
            lhsNet.remove(x)
            rhsNet.remove(z)
            break

The code should find a duplicate entry that exists in both lists and remove it. For some reason after execution I am left with:

lhsNet = ['p', 'p', 'p', 'p', '(3)He']

rhsNet = ['e+', 'nu_e', 'e+', 'nu_e', 'gamma', '(3)He', 'gamma', '(4)He']

Clearly it has removed all of the duplicate entries that exist in both lists EXCEPT for the last '(3)He' . Can anyone explain to me what is going wrong in my code and how to fix it?

Answer 1

I think that should work out for you:

new_lhsNet = list(set(lhsNet) - set(rhs_net))
new_rhsNet = list(set(rhsNet) - set(lhsNet))

Edit: Otherwise you can try the following as well:

lhsNet = [x for x in lhsNet if not x in rhsNet]
rhsNet = [x for x in rhsNet if not x in lhsNet]

The set() method from the upper example removes every duplicate within the list itself, which is probably not what you want. The lower example removes only the duplicates from another list without the duplicates within the list itself.

Answer 2

You shouldn't use break statement when you iterate If you just remove it and make your code look like.

    for x in lhsNet:
        for z in rhsNet:
            if x == z:
               lhsNet.remove(x)
               rhsNet.remove(z)

Everything will be working perfectly

Answer 3

删除break语句，它将根据需要运行。

Answer 4

Once the data is matched with rhsNet,the inner loop will break,it will not iterate through entire data of rhsNet list. So, Please remove the break statement in the code and able to get the unique values in both list.