[英]sql query update table with missing fields from another table
I have an issue with a SQL query/SP where I'm trying to update a table that has missing data in specific fields from another table where the data in those same fields exists and is valid. 我在SQL查询/ SP中遇到问题,在该问题中,我尝试更新另一个表中特定字段中缺少数据的表,而另一个表中存在相同字段且有效的数据。 The trick here is I would like to anchor on a value in the first table.
这里的技巧是我想锚定第一个表中的值。 I can make it work with a
INSERT INTO
/ SELECT FROM
combo, but it creates a duplicate record. 我可以使其与
INSERT INTO
/ SELECT FROM
组合一起使用,但是会创建重复记录。
Im using mysql 5.x. 我正在使用mysql 5.x. Here are the details.
这是详细信息。 The table with missing data is
thisweek
and the table with valid data is lastweek
. 数据丢失的表是
thisweek
,数据有效的表是lastweek
。 Field 1 is MACAddress
(which exists and is the anchor) and exists in both tables (for ex. BE:EF:BA:BE:CA:FE), Fields 2-10 in thisweek
are blank (''), but there is data in those same fields(Fields2-10) in table lastweek
. 字段1是
MACAddress
(存在并且是锚点)并且在两个表中都存在(例如BE:EF:BA:BE:CA:FE), thisweek
字段2-10为空白(''),但是上周表中相同字段(字段2-10)中的lastweek
。
UPDATE thisweek
SET thisweek.field2 = lastweek.field2
where thisweek.MACAddress = lastweek.MACAddress and thisweek.filed2 = '';
I know that query isn't anywhere close, so looking for help. 我知道查询还没有结束,因此需要帮助。 Again, the same
MACAddress
exists in both tables, with the only difference between tables being that field2 in thisweek
is blank (and it shouldn't be) and needs to be equal to lastweek.field2
for that MACAddress
. 同样,两个表中都存在相同的
MACAddress
,两个表之间的唯一区别是thisweek
field2为空白(并且不应为空),并且该MACAddress
必须等于lastweek.field2
。
Thanks all. 谢谢大家
you need to JOIN thisweek and lastweek tables. 您需要加入本周表和上周表。
UPDATE thisweek
JOIN lastweek
ON thisweek.MACAddress = lastweek.MACAddress
AND thisweek.field2 =''
SET thisweek.field2 = lastweek.field2
I think you want the following: 我认为您需要以下条件:
UPDATE tw
SET tw.Field2 = lw.Field2
FROM
ThisWeek tw
JOIN LastWeek lw ON tw.MACAddress = lw.MACAddress
WHERE
tw.Field2 = ''
update table1
inner join table2 on table1.id = table2.id and (table1.name = '' or table1.name is null)
set table1.name = table2.name;
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