[英]JSON returning null on response with jQuery $.ajax
I'm trying to get response on ajax post but returning NULL always instead. 我试图在ajax发布上获得响应,但总是返回NULL。
I'm thinking that already try everything that I can... but hope somebody will be able to solve it. 我以为已经尝试了所有可能的方法...但是希望有人能够解决它。 Thanks very much in advance.
首先十分感谢。 And if needs more information please tell me.
如果需要更多信息,请告诉我。
NOTE: PHP function not returning any data to JQuery ajax method - this link didn't help me 注意: PHP函数不会向JQuery ajax方法返回任何数据 -此链接对我没有帮助
Here is jquery code: 这是jQuery代码:
var post_id=3;
$.ajax({
type: "POST",
url: "profile/ajax_get_new_posts",
data: { post_id : post_id },
dataType: 'json',
success: function(data){
console.log(data);
var current_content = $("ol#posts_container").html();
$("ol#posts_container").html(data.content + current_content);
}
});
profile/ajax_get_new_posts (it is .php) profile / ajax_get_new_posts(.php)
function ajax_get_new_posts(){
header('Content-Type: application/json');
$post_id=$this->input->post('post_id');
$chat_messages_html='testing';
$result = array('status' => 'ok', 'content' => $chat_messages_html);
$result=json_encode($result);
return ($result);
exit();
}
If I try with var_dump($result);die(); 如果我尝试使用var_dump($ result); die(); gives me correct result:
给我正确的结果:
string(38) "{"status":"ok","content":"samoletite"}"
On the Response Headers gives me Content-Length:0 (it is testing on localhost... not www.mywebsite) 在响应标头上,我得到Content-Length:0(正在localhost上进行测试...,而不是www.mywebsite)
Remote Address:[::1]:80
Request URL:http://www.mywebsite/bg/profile/ajax_get_new_posts
Request Method:POST
Status Code:200 OK
Request Headersview source
Accept:application/json, text/javascript, */*; q=0.01
Accept-Encoding:gzip,deflate
Accept-Language:en-US,en;q=0.8
Connection:keep-alive
Content-Length:9
Content-Type:application/x-www-form-urlencoded
Host:localhost
Origin:http://localhost
Referer:http://www.mywebsite/bg/profile
User-Agent:Mozilla/5.0 (Windows NT 6.3; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/38.0.2125.111 Safari/537.36
X-Requested-With:XMLHttpRequest
Form Dataview sourceview URL encoded
post_id:3
Response Headersview source
Connection:Keep-Alive
Content-Length:0
Content-Type:application/json
Date:Fri, 31 Oct 2014 13:24:56 GMT
Keep-Alive:timeout=5, max=97
.......
Console.log gives me: Console.log给我:
null --->ajaxPostProfile.js:28
Uncaught TypeError: Cannot read property 'content' of null --->ajaxPostProfile.js:31
Instead to use return ($result);
而是使用
return ($result);
, use echo
. ,使用
echo
。 Like this: 像这样:
function ajax_get_new_posts(){
header('Content-Type: application/json');
$post_id=$this->input->post('post_id');
$chat_messages_html='testing';
$result = array('status' => 'ok', 'content' => $chat_messages_html);
$result=json_encode($result);
echo $result;
exit();
}
And test again. 并再次测试。
you can return json data in PHP using following syntax: 您可以使用以下语法在PHP中返回json数据:
header('Content-Type: application/json');
echo json_encode($result);
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