[英]Mongoose find array with $in
Team.find({
'_id': { $in: [
teamIds
] }
}, function(err, teamData) {
console.log("teams name " + teamData);
});
This code gives us undefined back.. But in the var teamIds is this: 这段代码给了我们未定义的返回..但在var teamIds是这样的:
545646d5f5c1cce828982eb7,
545646d5f5c1cce828982eb8,
54564af5c9ddf61e2b56ad1e,
54564c1f1de201782bcdb623,
54564d2fc660a7e12be6c7a2,
54564df985495f142c638f9f,
54564eadb511f1792c9be138,
54564ec40cf6708a2cd01c81,
54564ee495f4aea22cf23728
Does anybody see the error? 有人看到错误吗?
If teamIds
is already an array, then you shouldn't wrap it in another array: 如果teamIds
已经是一个数组,那么你不应该将它包装在另一个数组中:
Team.find({
'_id': { $in: teamIds }
}, function(err, teamData) {
console.log("teams name " + teamData);
});
Or, if teamIds
is a string of comma-separated id values, you need to convert it into an array of values using split
: 或者,如果teamIds
是逗号分隔的id值字符串,则需要使用split
将其转换为值数组:
Team.find({
'_id': { $in: teamIds.split(',') }
}, function(err, teamData) {
console.log("teams name " + teamData);
});
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