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在调用中缺少参数#1的参数

[英]Missing argument for parameter #1 in call

I have a lazy parameter that I'm attempting to call a helper function in: 我有一个懒惰的参数,我试图调用辅助函数:

class ColumnNode: SCNNode {

    lazy var upperColumnNode: SCNNode = {
        return buildColumPart()
    }()

    func buildColumPart() -> SCNNode {
        var node = SCNNode()
        ...
        return node
    }
}

Unfortunately on line return buildColumPart() I am getting: 不幸的是在线return buildColumPart()我得到:

Missing argument for parameter #1 in call

What exactly does this mean and how do I fix it? 这究竟是什么意思,我该如何解决?

You need to use self to access instance methods in lazy properties: 您需要使用self来访问延迟属性中的实例方法:

class ColumnNode: SCNNode {

    lazy var upperColumnNode: SCNNode = {
        return self.buildColumPart()
    }()

    func buildColumPart() -> SCNNode {
        var node = SCNNode()
        ...
        return node
    }
}

Interestingly enough, the reason it's complaining about parameter #1 is that instance methods are actually class methods that take an instance as a parameter and return a closure with the instance captured - instead of self.buildColumPart() , you could instead call buildColumPart(self)() . 有趣的是,它抱怨参数#1的原因是实例方法实际上是类方法,它将实例作为参数并返回一个捕获实例的闭包 - 而不是self.buildColumPart() ,你可以改为调用buildColumPart(self)()

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