Python-编写一个函数以打开.txt文件并返回其中的单词总数

Question

Been trying to do this for a while but for some reason i cant get my head around this simple code. Dont need to worry about punctuation, its just plain text. At the moment all i have is:

def wc(filename):

    f = open(filename, 'r')    # Read
    words = f.readlines()
    f.close()
    print int(filename.split())
    p = 1
    for word in words:
        p += words
    return p

been looking for an answer for a while but can only find examples where they count specific words.

Answer 1

f = open(filename)    # Read
words = f.read()
f.close()
words = words.split()
print len(words)

Answer 2

split can take a parameter sep which specifies what characters to split on (the separator).

The string module has some constants including punctuation and whitespace .

Putting them together you get

import string

filename = 'words.txt'

with open(filename) as f:
    words = f.read().split(string.whitespace + string.punctuation)

print len(words)

Answer 3

This one gives you lines

words = f.readlines()

You need to split word variable inside for via .split() method.

word_count += len(word.split())

Answer 4

with open(filename, 'r+') as f:
    words = f.read()
words = words.split(' ')
words_nbr = len(words)
print(words_nbr)