如何在php中将对象传递给隐藏形式？

Question

I have an object called $todovalues and a form. I need to pass the entirety of the todovalues object through the form.

My form looks like -

<form action="" method="post">
<input class="todobuttons" type="submit" name="delete" value="delete">
<input class="todobuttons" type="submit" name="edit" value="edit">
<input type="hidden" name="post_item_info"
value="<?php echo serialize($todovalues); ?>">
</form>

I can access the values in $todovalues by using something like echo $todovalues->text.

I have tried to use serialize, json_encode, and a mixture of both. However, when I try to access the post value it is always empty.

Is there a way to take my object and add it to the hidden input without having to create individual hidden inputs for each piece of the object that I want?

json_encode($todovalues);
json_encode(serialize($todovalues));
serialize($todovalues);

None of the above have been functional yet. Is there no simplified method to pass the whole of an object without iterating through the object first? It just seems like a waste of space to have to create hidden inputs for each item in the object.

EDIT -

When I use json_encode() I see the following so I know it SHOULD exist -

<input type="hidden" name="post_item_info" value="{" id_auto":"3","id":"1","id_list":"1","completed":"0","incident_notes":"apple"}"="">

Answer 1

Possibly, you try to encode object. Try encode an array:

json_encode((array) $todovalues);

UPD. Or, it can happens because your html looks like this:

<input value="{"id":3....}"> (a lot of ")

You can try base64_encode()

Answer 2

The json_encode was breaking due to the fact that I created the input using double quotes.

The system saw -

value="{" stuffGoesHere "

I switched to single quotes -

value=' {"stuffGoesHere" '

It works perfect now.