Python 3：将2个元素列入字典

Question

Python3 OMG, sorry for a probably often repeated question in one way or another. For me, manipulating lists has always been like a black box of headaches, and I've been battling for an hour now with no results.

I have a list in the form:

[('John', 'first@email.com'), ('John', 'second@email.com'), ('Jack', 'third@email.com')]

I would like to transform this into an iterable dictionary (that I could then bulk insert as a document using pymongo) so that it looks like this:

 new_posts = [{"sender": "John",
               "email": "first@email.com"},
              {"sender": "John",
               "email": "second@email.com"},
              {"sender": "Jack",
               "email": "third@email.com"}]

How would this be achievable in an easy to read and efficient manner?

Answer 1

You can try

>>> a = [('John', 'first@email.com'), ('John', 'second@email.com'), ('Jack', 'third@email.com')]
>>> [dict([('sender', x[0]), ('email',x[1])]) for x in a]
[{'sender': 'John', 'email': 'first@email.com'}, {'sender': 'John', 'email': 'second@email.com'}, {'sender': 'Jack', 'email': 'third@email.com'}]

This will convert list to dict

Answer 2

data = [('John', 'first@email.com'), ('John', 'second@email.com'), ('Jack', 'third@email.com')]
new_posts = []
for i in range(len(data)):
    new_post = {}
    new_post["sender"] = data[i][0]
    new_post["email"] = data[i][1]
    new_posts.append(new_post)

Another way of solving it..

Answer 3

your_list = [('John', 'first@email.com'), ('John', 'second@email.com'), ('Jack', 'third@email.com')]
your_result = [{'sender': sender, 'email': email} for sender, email in your_list]