[英]C programming, fprintf() not working correctly
Probably a silly mistake I am doing here. 我在这里可能是一个愚蠢的错误。
FILE *fp;
fp = fopen("test.txt", "a+");
fprintf(fp, time_stamp(),"FLAG 1, Timestamp : %s\n");
fclose(fp);
I am getting timestamp from a function But The file writing only timestamp, not the flag If I remove timestamp, FLAG 1 printing. 我从一个函数获取时间戳,但是该文件仅写时间戳,而不写标志。如果删除时间戳,则打印FLAG 1。 But Not getting together. 但是不在一起。 ie 即
Flag 1, Timestamp : 20141005141116
The output I am getting in test.txt like 我在test.txt中得到的输出像
20141005145640201410051456402014100514564020141005145640201410051456412014100514564120141
Not going to new line and print like: 不打算换行并打印:
Flag 1, Timestamp : 20141005141116
Flag 1, Timestamp : 20141005141117
Flag 1, Timestamp : 20141005141118
..... like that ..... 像那样
Please solve this issue 请解决这个问题
You have the arguments to fprintf()
in the wrong order. 您以错误的顺序输入了fprintf()
的参数。 Look at the manual page 's prototype: 查看手册页的原型:
int fprintf(FILE *stream, const char *format, ...);
Clearly, the formatting string comes before the things being formatted (the variable part ...
). 显然,格式化字符串位于要格式化的事物之前 (可变部分...
)。
Assuming time_stamp()
returns a static string, your code should be: 假设time_stamp()
返回一个静态字符串,则您的代码应为:
fprintf(fp, "FLAG 1, Timestamp : %s\n", time_stamp());
fprintf()
参数应如下所示:
fprintf(fp, "FLAG 1, Timestamp : %s\n", time_stamp());
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