无法将PHP嵌入CSS样式的单选按钮中以填充表单

Question

I'm currently writing a program that allows information in a database to be edited by populating a web form.

However, the web page is formatted with customized radio buttons and I seem to be having trouble embedding PHP inside the HTML tags. My understanding is that combinations of CSS and HTML don't allow PHP to written inside. Is that the problem here? (The document is saved as a PHP file)

 <div id="radio4">
     <div class="radio1" >  
         <input id="mgender" type="radio" name="GENDER" value="m" <?php echo ($GENDER == 'm') ?  "checked" : "" ;  ?>> 
             <label for="mgender"></label></div></div>

 <div id="radio5">       
     <div class="radio2">  
         <input id="fgender" type="radio" name="GENDER" value="f" <?php echo ($GENDER  == 'f') ? "checked" : "" ; ?>>
             <label for="fgender"></label></div></div>

If so, how can I fix it?

Answer 1

try with this regular expression :

<div id="radio4">
     <div class="radio1" >  
         <input id="mgender" type="radio" name="GENDER" value="m" <?php if($GENDER=='m'){echo"checked";}?> /> 
             <label for="mgender">Male</label></div></div>

 <div id="radio5">       
     <div class="radio2">  
         <input id="fgender" type="radio" name="GENDER" value="f" <?php if($GENDER=='f'){echo"checked";}?> />
             <label for="fgender">Female</label></div></div>

Answer 2

I still haven't been able to figure this out. I thought writing it the above way worked, but it was just automatically checking one of the radio buttons.

I think it may be a configuration issue associated with my Apache server, or something in the php.ini files. Anyone have any knowledge of this?

In my text editor the close tag at the end of the php statement stops being read as code.

So, for example in this statement:

 <input id="mgender" type="radio" name="GENDER" value="m" <?php echo ($GENDER == 'f') ? checked="checked" : "" ; ?> [nothing read after this point] />

*edited to add code.