在bash中使用sed将字符串替换为heredoc

Question

In a bash script I need to replace a placeholder string in a file with some heredoc. How do I do that?

eg sed -i 's/PLACEHOLDER_TEXT/$HEREDOC/g' > file.txt where

<<HEREDOC
Some multiple
lines of
text to replace PLACEHOLDER_TEXT
HEREDOC

Answer 1

pass trhough a temporary file and avoid a substitute due to behavior of replace pattern special char that can occur (like & , \\x )

so

cat > /tmp/HereFile <<HEREDOC
Some multiple
lines of
text to replace PLACEHOLDER_TEXT
HEREDOC

sed '/PLACEHOLDER_TEXT/ {
   r /tmp/HereFile
   d
   }' YourFile
rm /tmp/HereFile 

Answer 2

Just flatten it out (you can change the # if that may appear in your data) and put the newlines back in afterward like:

sed "s/PLACEHOLDER_TEXT/$(echo "$HEREDOC"|tr "\n" "#")/g;s/#/\n/g" file.txt

To build the $HEREDOC variable:

$> export HEREDOC=$(cat<<EOF

    > what is going 
    > on with 
    > this 
    > thing
    > EOF
    > )

Answer 3

Try this command:

val=$(tr '\n' ' ' < PlaceHolderText.txt); sed "s/PLACEHOLDER/$val/" File.txt

Example:

sdlcb@Goofy-Gen:~/AMD$ cat PlaceHolderText.txt
Some multiple
lines of
text to replace

sdlcb@Goofy-Gen:~/AMD$ cat File.txt
This is a text with PLACEHOLDER for some additional data.

sdlcb@Goofy-Gen:~/AMD$ val=$(tr '\n' ' ' < PlaceHolderText.txt); echo $val; sed "s/PLACEHOLDER/$val/" File.txt
This is a text with Some multiple lines of text to replace  for some additional data.