[英]Pandas Python DataFrames: How to split dataframes
I have a df 我有一个df
df = pd.DataFrame(np.random.randn(11,3))
0 1 2
0 0.102645 -1.530977 0.408735
1 1.081442 0.615082 -1.457931
2 1.852951 0.360998 0.178162
3 0.726028 2.072609 -1.167996
4 -0.454453 1.310887 -0.969910
5 -0.098552 -0.718283 0.372660
6 0.334170 -0.347934 -0.626079
7 -1.034541 -0.496949 -0.287830
8 1.870277 0.508380 -2.466063
9 1.464942 -0.020060 -0.684136
10 -1.057930 0.295145 0.161727
How can I split this in a given number of subsections, lets say 2 for now. 我如何将其分成给定数量的小节,现在说2个。
Something like this 像这样
0 1 2
0 0.102645 -1.530977 0.408735
1 1.081442 0.615082 -1.457931
2 1.852951 0.360998 0.178162
3 0.726028 2.072609 -1.167996
4 -0.454453 1.310887 -0.969910
0 1 2
5 -0.098552 -0.718283 0.372660
6 0.334170 -0.347934 -0.626079
7 -1.034541 -0.496949 -0.287830
8 1.870277 0.508380 -2.466063
9 1.464942 -0.020060 -0.684136
10 -1.057930 0.295145 0.161727
Ideally I would like to use np.array_split(df, 2) but it throws an error as its not an array. 理想情况下,我想使用np.array_split(df,2),但是它抛出错误,因为它不是数组。
Is there a built in function to do this? 有内置的功能可以做到这一点吗? I don't particularly want to use df.loc[a:b] because its difficult to calculate the start and end depending on the given number of sub-dataframes needed. 我不是特别想使用df.loc [a:b],因为它很难根据所需的给定子数据帧数来计算开始和结束。
Try the following. 尝试以下方法。 It should return an array of n sub-dataframes if concatenated would return the original dataframe in question. 如果串联将返回所讨论的原始数据帧,则它应返回n个子数据帧的数组。
import math
def split(df, n):
size = math.ceil(len(df) / n)
return [ df[i:i + size] for i in range(0, len(df), size) ]
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