如何从请求主体获得结果

Question

I use Node js

Using cheerio library, I try to parse a page.

By request, I got body of a webpage.

In this body, I want to get contents of

Below is my code :

var cheerio = require('cheerio');
var request = require('request');

 request('http://query.yahooapis.com/v1/public/yql?q=select%20*%20from%20html%20where%20url%3D%22http%3A%2F%2Ffortune.daum.net%2Fexternal%2F4%2Frun%2Fstar_free%2Findex.php%22%20and%0A%20%20%20%20%20%20xpath%3D%27%2F%2Ftd%5Bcontains(%40style%2C%22font-family%3A%EA%B5%B4%EB%A6%BC%3B%20font-size%3A12px%3B%20color%3A%23333333%3B%20line-height%3A18px%3B%20padding-right%3A10px%22)%5D%27&diagnostics=true&env=store%3A%2F%2Fdatatables.org%2Falltableswithkeys',
function(error,response,body){ 

console.log(body);
//var info =JSON.parse(body);
});

The result of 'console.log(body)' is 'XML'. And I want to get contents of

And Can I convert it to JSON??

Answer 1

根据Yahoo的文档 ，您只需要添加format=json查询字符串参数。