[英]How to get matched sub documents from mongodb?
I have a collection like this 我有这样的集合
{
"_id" : ObjectId("545dad3562fa028fb48832f0"),
"key" : "123456",
"members" : [
{
"name" : "Shiva",
"country" : "India",
"profession" : "Software"
},
{
"name" : "Neil",
"country" : "Australia",
"profession" : "Software"
},
{
"name" : "anil",
"country" : "India",
"profession" : "Software"
}
]
}
Now i want to retrieve the records with country India. 现在我想用国家印度检索记录。 When i tried like this
当我尝试这样的时候
db.user_details.find({ 'key' :'123456','members':{$elemMatch:{'country': "India"}}}, {'members.$': 1}).pretty()
When executed the above code i am getting only first occurrence, How to get all the matched sub documents(like name:Shiva
and name:Anil
) from that document 执行上面的代码时,我只是第一次出现,如何从该文档获取所有匹配的子文档(如
name:Shiva
和name:Anil
)
The $elemMatch
operator along the the counterpart positional $
operator will only currently match the first element that meets the conditions specified. 对应位置
$
运算符上的$elemMatch
运算符目前仅匹配满足指定条件的第一个元素。
In order to get "more than one" match, the best method is to use the aggregation framework: 为了获得“多个”匹配,最好的方法是使用聚合框架:
db.user_details.aggregate([
# Always match first to at least find the "documents" with matching elements
{ "$match": {
"members.country": "India"
}},
# Use $unwind to "de-normalize" the array as individual documents
{ "$unwind": "$members" },
# Then match again to "filter" the content down to matches
{ "$match": {
"members.country": "India"
}},
# Group back to keep an array
{ "$group": {
"_id": "$_id",
"key": { "$first": "$key" },
"members": { "$push": "$members" }
}}
])
That is the basic process for "filtering" more than one match from an array. 这是从数组中“过滤”多个匹配的基本过程。 The basic projection cannot currently do it.
基本投影目前无法做到。
Which returns this: 哪个返回:
{
"_id" : ObjectId("545dad3562fa028fb48832f0"),
"key" : "123456",
"members" : [
{
"name" : "Shiva",
"country" : "India",
"profession" : "Software"
},
{
"name" : "anil",
"country" : "India",
"profession" : "Software"
}
]
}
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