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来自同一Go程序的不同输出

[英]Different output from the same Go program

Here is my Go code: http://play.golang.org/p/CDUagFZ-rk 这是我的Go代码: http//play.golang.org/p/CDUagFZ-rk

package main

import "fmt"

func main() {
    var max int = 0
    for i := 0; i < 1000000; i++ {
        var len int = GetCollatzSeqLen(i)
        if len > max {
            max = len
        }
    }

    fmt.Println(max)

}

func GetCollatzSeqLen(n int) int {
    var len int = 1
    for n > 1 {
        len++
        if n%2 == 0 {
            n = n / 2
        } else {
            n = 3*n + 1
        }
    }
    return len

}

On my local machine, when I run the program, I get 525 as the output. 在我的本地机器上,当我运行程序时,我得到525作为输出。 When I run it on the Go Playground, the output is 476. 当我在Go Playground上运行时,输出为476。

I am wondering what's different. 我想知道有什么不同。

It's because of the implementation-specific size of int , 32 or 64 bits. 这是因为int的实现特定大小,32位或64位。 Use int64 for consistent results. 使用int64获得一致的结果。 For example, 例如,

package main

import "fmt"

func main() {
    var max int64 = 0
    for i := int64(0); i < 1000000; i++ {
        var len int64 = GetCollatzSeqLen(i)
        if len > max {
            max = len
        }
    }

    fmt.Println(max)

}

func GetCollatzSeqLen(n int64) int64 {
    var len int64 = 1
    for n > 1 {
        len++
        if n%2 == 0 {
            n = n / 2
        } else {
            n = 3*n + 1
        }
    }
    return len

}

Output: 输出:

525

Playground: http://play.golang.org/p/0Cdic16edP 游乐场: http//play.golang.org/p/0Cdic16edP


The Go Programming Language Specification Go编程语言规范

Numeric types 数字类型

\n int32 the set of all signed 32-bit integers (-2147483648 to 2147483647) int32所有带符号的32位整数的集合(-2147483648到2147483647)\n int64 the set of all signed 64-bit integers (-9223372036854775808 to 9223372036854775807) int64所有带符号的64位整数的集合(-9223372036854775808到9223372036854775807) 

The value of an n-bit integer is n bits wide and represented using two's complement arithmetic. n位整数的值是n位宽,并使用二进制补码算法表示。

There is also a set of predeclared numeric types with implementation-specific sizes: 还有一组具有特定于实现的大小的预先声明的数字类型:

\n uint either 32 or 64 bits uint 32或64位\n int same size as uint 与uint相同的大小 

To see the implementation-specific size of int , run this program. 要查看特定于实现的int大小,请运行此程序。

package main

import (
    "fmt"
    "runtime"
    "strconv"
)

func main() {
    fmt.Println(
        "For "+runtime.GOARCH+" the implementation-specific size of int is",
        strconv.IntSize, "bits.",
    )
}

Output: 输出:

For amd64 the implementation-specific size of int is 64 bits.

On Go Playground: http://play.golang.org/p/7O6dEdgDNd 在Go Playground: http//play.golang.org/p/7O6dEdgDNd

For amd64p32 the implementation-specific size of int is 32 bits.

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