[英]How to convert a method from boolean to int (java)?
so I have to build a Sudoku game in Java. 所以我必须用Java构建Sudoku游戏。 I am able confirm in my method that the numbers 1 to 9 only appear once in each row/column.
我可以用我的方法确认数字1到9在每一行/列中只出现一次。 However, I have this set up as a boolean and can not for the life of me figure out how to convert this to an integer (so that I can return the row/column where the error occurs).
但是,我将此设置为布尔值,并且无法终生弄清楚如何将其转换为整数(以便我可以返回发生错误的行/列)。
public static boolean rowColumnCheck(int[][] array) {
for (int i = 0; i < 9; i++) {
boolean[] rowArray = new boolean[9];
boolean[] columnArray = new boolean[9];
for (int j = 0; j < 9; j++) {
int currentNumberRow = array[i][j];
int currentNumberColumn = array[j][i];
if ((currentNumberRow < 1 || currentNumberRow > 9)
&& (currentNumberColumn < 1 || currentNumberColumn > 9)) {
return false;
}
rowArray[currentNumberRow - 1] = true;
columnArray[currentNumberColumn - 1] = true;
}
for (boolean booleanValue : rowArray) {
if (!booleanValue) {
return false;
}
}
for (boolean booleanValue : columnArray) {
if (!booleanValue) {
return false;
}
}
}
return true;
}
You can't. 你不能 Each method basically has just a return type and a boolean is not compatible with an Integer.
每个方法基本上只有一个返回类型,并且布尔值与Integer不兼容。 What you could do is change the return type to Integer or to Pair if you need to return a set of coordinates and return null if is not there.
如果需要返回一组坐标,则可以将返回类型更改为Integer或Pair,如果不存在则返回null。
I guess it would be something like this. 我猜可能是这样的。 If null there was no error, and on the pair is the error location.
如果为null,则没有错误,并且在错误对上是错误位置。
public static Pair rowColumnCheck(int[][] array) {
Pair <Integer, Integer> p = null;
for (int i = 0; i < 9; i++) {
boolean[] rowArray = new boolean[9];
boolean[] columnArray = new boolean[9];
for (int j = 0; j < 9; j++) {
int currentNumberRow = array[i][j];
int currentNumberColumn = array[j][i];
if ((currentNumberRow < 1 || currentNumberRow > 9)
&& (currentNumberColumn < 1 || currentNumberColumn > 9)) {
p = new Pair<Integer, Integer>(i, j);
return p;
}
rowArray[currentNumberRow - 1] = true;
columnArray[currentNumberColumn - 1] = true;
}
// Not really sure why you are doing this?
for (boolean booleanValue : rowArray) {
if (!booleanValue) {
return null;
}
}
for (boolean booleanValue : columnArray) {
if (!booleanValue) {
return null;
}
}
}
return null;
}
I have a feeling you want sometimes to return a row/column pair, sometimes a row, and sometimes a column. 我有一种感觉,您希望有时返回行/列对,有时返回行,有时返回列。 If this is right, then you need to create an extra class:
如果正确,那么您需要创建一个额外的类:
public class RowCol {
public final int row;
public final int col;
public RowCol(int row, int col) {
this.row = row;
this.col = col;
}
}
Now when you want to identify the place where the error occurred, you can 现在,当您要确定错误发生的位置时,您可以
return new RowCol(i,j);
or to indicate a row without specifying a column 或表示未指定列的行
return new RowCol(i,-1);
and similarly for a column 和类似的列
return new RowCol(-1,j);
The return type of your method will be RowCol
, and when you get one back from your method, you'll be able to interrogate its row
and col
fields to find out the co-ordinates of the return value. 方法的返回类型将为
RowCol
,当您从方法中获得返回值时,您可以查询其row
和col
字段以找出返回值的坐标。
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