SQL Server简单查询联接表本身

Question

I have a table GAMES which holds data about past games played. The point of this query is to find all the games that have been played on the same date and print the date, the two teams that played and the result. The table is set up like this:

GAMES

Home   | Visitors|Date      |Result
-------------------------------------
Bengals| Browns  | 1/1/2012 | Tie
Browns | Bengals | 1/1/2012 | Loss
Giants | Jets    | 4/2/2013 | Win
Giants | Cowboys | 4/2/2013 | Loss
Bears  | Ravens  | 5/3/2012 | Tie
Bills  | Dolphins| 10/11/2014| Win
...

I think the solution is to join the tables in a query similar to this

select 
    A.Date, A.Home, A.Visitors, A.Result
from 
    GAMES as A, GAMES as B
where 
    A.Date = B.Date 
    and A.Home = B.Visitors;

but in this specific query it will only return one game first of all, there are 6 games in total that should show up, and only returns the values from Table A. Is there a way in which I can write the query so it finds all games at once rather than tailoring a specific query to find each one? Thanks.

Desired results would be in the form of:

1 2012-1-1 Bengals Browns Tie
2 2012-1-1 Browns Bengals Loss
3 2013-4-2 Giants Jets Win
4 2013-4-2 Giants Cowboys Loss
etc. 

Answer 1

Ok, so sound like what you're trying to do is find dates where more than one game occurred. In that case

SELECT a.Date, count(*) as CountOfDate
FROM GAMES a
GROUP BY a.Date
HAVING count(*) > 1

Answer 2

How about something like this?

SELECT
    A.Date, A.Home, A.Visitors, A.Result
FROM 
    GAMES as A
WHERE EXISTS (SELECT * 
              FROM GAMES as B 
              WHERE A.DATE = B.DATE 
                AND (A.Home <> B.Home 
                OR   A.Visitors <> B.Visitors))
ORDER by A.Date ASC