使用awk替换列

Question

I have 3 files

1file

 14/09/15
 14/09/15
 14/09/15
 14/09/15
 14/09/15

2file

14/09/01 
14/09/01
14/09/01
14/09/01
14/09/01

and 3file

15/09/14,11-37,01/09/14,1224A,0G,71%,RGS
15/09/14,11-41,01/09/14,2700A,0G,94%,RAN
15/09/14,11-43,01/09/14,2701A,0G,100%,RAN
15/09/14,11-44,01/09/14,2701B,0G,92%,RAN
15/09/14,11-46,01/09/14,2708A,0G,88%,RAN

I need replace the column 1 from 3f with the column 1 from 1f and the third from 3f with the column 1 of 2f

How can I replace using awk?

Answer 1

The following awk code will be usefull

$ awk   'BEGIN{OFS=FS=","}NF==1{line[FNR]=line[FNR]","$0} NF>1{split(line[FNR], a); $1=a[2]; $2=a[3]; print $0}' 1file 2file 3file
14/09/15,14/09/01,01/09/14,1224A,0G,71%,RGS
14/09/15,14/09/01,01/09/14,2700A,0G,94%,RAN
14/09/15,14/09/01,01/09/14,2701A,0G,100%,RAN
14/09/15,14/09/01,01/09/14,2701B,0G,92%,RAN
14/09/15,14/09/01,01/09/14,2708A,0G,88%,RAN

What it does??

• OFS=FS="," sets output field separator OFS and field separator FS as ,

• NF==1{line[FNR]=line[FNR]","$0} If number of fields/columsn , NF is one, save the value in line variable seperated by commas

• NF>1{split(line[FNR], a); $1=a[2]; $2=a[3]; print $0} NF>1{split(line[FNR], a); $1=a[2]; $2=a[3]; print $0} takes the action when NF greater than one

  • split(line[FNR], a); split the line variable to array a

  • $1=a[2]; $2=a[3]; sets the first and second column

  • print $0 prints the entire record