[英]laravel raw query doesn't return results
i have the code below 我有下面的代码
$id = 1;
$idz = 3;
$nums = DB::select(DB::raw('select * from chat_user where user_id in (?, ?) and chat_id in (select chat_id from chat_user group by chat_id having count(*) > 1)'), array($id, $idz));
return $nums->count();
here i have a table named "user_chat" and i want to find out if i select two rows by their "user_id" do they have the same "chat_id". 在这里,我有一个名为“ user_chat”的表,我想确定是否通过“ user_id”选择两行,它们是否具有相同的“ chat_id”。 the code works fine when i test it in phpmyadmin's sql section and return the result. 当我在phpmyadmin的sql部分中对其进行测试并返回结果时,代码工作正常。
select * from chat_user where user_id in (1, 3) and chat_id in (select chat_id from chat_user group by chat_id having count(*) > 1)
but when i write it in laravel's style i get this error: 但是当我以laravel的风格编写它时,出现此错误:
Call to a member function count() on a non-object
any help would be really great! 任何帮助都将非常棒!
DB::select
returns an array, not an object. DB::select
返回一个数组,而不是对象。
Use count($nums)
instead. 请改用count($nums)
。
when you use DB::select()
, the returned thing is the result. 当您使用DB::select()
,返回的是结果。 not the query builder object. 不是查询生成器对象。
you can tackle this in three ways. 您可以通过三种方式解决此问题。
SELECT COUNT(id)....
运行另一个SELECT COUNT(id)....
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