[英]In SQL Joins - one to many select one column multiple times based upon context
I have two tables, one containing records, and one logging date time stamps on when operations have been performed. 我有两个表,一个包含记录,一个包含执行操作时的日志记录日期时间戳。 Example:
例:
CREATE TABLE MyRecord(
RecNumber INT IDENTITY(1,1) PRIMARY KEY
,TaskDetail NVARCHAR(200)
)
CREATE TABLE MyLOG(
LogID INT IDENTITY(1,1) PRIMARY KEY
,DTStamp DATETIME2(2)
,TaskName NVARCHAR(10)
,RecNumber
,FOREIGN KEY ( RecNumber ) references MyRecord(RecNumber )
)
So for example if I had 例如,如果我有
|RecNumber|TaskDetail
| 1 | Some Task
|LogID|DTStamp |TaskName |RecNumber|
| 1 | 2014-11-11 00:00:00.00|StartTask | 1 |
| 2 | 2014-11-11 00:01:00.00|EndTask | 1 |
I would like a query to return: 我想查询返回:
|RecNumber|TaskDetail| Start Time | End Time |
| 1 | Some Task| 2014-11-11 00:00:00.00 | 2014-11-11 00:01:00.00|
Now I know I could do this with nested select statements to get the start and end time. 现在,我知道可以使用嵌套的select语句执行此操作以获取开始时间和结束时间。 Using a join I could get the start time OR the end time.
使用联接可以获取开始时间或结束时间。 How do I get both without using nested SQL?
在不使用嵌套SQL的情况下如何获得两者? OR - is nested select statements the best way to do this?
或-嵌套选择语句是执行此操作的最佳方法吗?
Maybe I am going about this all wrong. 也许我要解决所有这些错误。
Another way is conditional aggregation: 另一种方法是条件聚合:
select r.recnumber,
r.taskdetail,
max(case when l.taskname = 'StartTask' then l.dtstamp end) as start_time,
max(case when l.taskname = 'EndTask' then l.dtstamp end) as end_time
from myrecord r
join mylog l
on r.recnumber = l.recnumber
group by r.recnumber,
r.taskdetail
You can do this in various ways. 您可以通过多种方式执行此操作。 Here is a way just using
join
s, assuming there is at most one matching row of each type: 这是一种使用
join
的方法,假设每种类型最多有一个匹配行:
select r.*, ls.DTStamp as StartTask, le.DTStamp as EndTask
from MyRecord r left join
MyLog ls
on r.recNumber = ls.recNumber and ls.TaskName = 'StartTask' left join
MyLog le
on r.recNumber = le.recNumber and le.TaskName = 'EndTask;
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.