在Python中获取文件路径的特定部分

Question

I have a path string like

'/path/eds/vs/accescontrol.dat/d=12520/file1.dat'

Q1: How can I get only accescontrol.dat from the path.

Q2: How can I get only /path/eds/vs/accescontrol.dat from the path.

Answer 1

You could use regular expressions

import re
ma = re.search('/([^/]+\.dat)/d=', path)
print ma.group(1)

Answer 2

import re

url = '/path/eds/vs/accescontrol.dat/d=12520/file1.dat'
match = re.search('^(.+/([^/]+\.dat))[^$]', url)

print match.group(1)
# Outputs /path/eds/vs/accescontrol.dat
print match.group(2)
# Outputs accescontrol.dat

I edited this to work in python2 and to answer both questions (the earlier regex answer above only answers the first of the two)

Answer 3

A simple solution is to use .split() :

Q1:

str = '/path/eds/vs/accescontrol.dat/d=12520/file1.dat'
[x for x in str.split('/') if x[-4:] == '.dat']

gives:

['accescontrol.dat','file1.dat']

A similar trick will answer Q2.

For more advanced file path manipulation I would recommend reading about os.path
https://docs.python.org/2/library/os.path.html#module-os.path

Answer 4

I would recommend separating each level of folder/file into strings in a list.

path = '/path/eds/vs/accescontrol.dat/d=12520/file1.dat'.split("/")

This makes path = ['path', 'eds', 'vs', 'accescontrol.dat', 'd=12520', 'file1.dat']

Then from there, you can access each of the different parts.

Answer 5

Why not this way

from pathlib import Path
h=r'C:\Users\dj\Pictures\Saved Pictures'
path = Path(h)
print(path.parts)

---

Path: .
('C:\\', 'Users', 'dj', 'Pictures', 'Saved Pictures')