SQL语句仅选择其中一列中包含最大值的行

Question

I have the following table:

select * from [Auction].[dbo].[Bids]

I need to select a row with the highest BidValue. When I do

SELECT bids.itemId, max(bids.[bidValue]) as HighestBid
FROM [Auction].[dbo].[Bids] bids
WHERE bids.itemId = 2
GROUP BY bids.itemId

I get the right row:

... but when I add two other fields it doesn't work (I know it shows 3 rows because of the Group by, but it throws an error if I don't include those fields in group by):

SELECT bids.itemId, max(bids.[bidValue]) as HighestBid, bids.submittedBy, bids.submittedOn
FROM [Auction].[dbo].[Bids] bids
WHERE bids.itemId = 2
GROUP BY bids.itemId, bids.submittedBy, bids.submittedOn

So, I need it do display one row with itemId, HighestBid, submittedBy, and submittedOn.

Any help is appreciated!

Answer 1

您可以简单地执行以下操作：

select TOP 1 * from Bids where ItemId = 2 order by BidValue desc

Answer 2

尝试这个

select top 1 * from Bids order by BidValue desc

Answer 3

if more then one highest value then use

select TOP (1) with ties * 
from Bids where ItemId = 2 order by BidValue desc