[英]How to run hello world program using spring maven?
I have started to learn spring and trying to create simple hello world application using maven in sts. 我已经开始学习spring并尝试在sts中使用maven创建简单的hello world应用程序。 Please anyone what am doing wrong in this code?
请任何人在这段代码中做错了什么?
index.jsp : index.jsp:
<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Spring4 MVC -HelloWorld</title>
</head>
<body>
<h1>Hello : ${name}</h1>
</body>
</html>
web.xml : web.xml:
<?xml version="1.0" encoding="ISO-8859-1" ?>
<web-app xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"
version="2.4">
<display-name>Archetype Created Web Application</display-name>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/dispatcher-servlet.xml</param-value>
</context-param>
<listener>
<listener-class>
org.springframework.web.context.ContextLoaderListener
</listener-class>
</listener>
</web-app>
dispatcher-servlet.xml : dispatcher-servlet.xml:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd">
<context:component-scan base-package="com.helloworld" />
<bean
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix">
<value>/WEB-INF/views/</value>
</property>
<property name="suffix">
<value>index.jsp</value>
</property>
</bean>
</beans>
HelloWorldController.java : HelloWorldController.java:
@Controller
public class HelloWorldController {
/**
* @param name
* @param model
* @return string
*/
@RequestMapping("/hello")
public String hello(@RequestParam(value="name", required=false, defaultValue="World") String name, Model model) {
model.addAttribute("name", name);
return "helloworld";
}
}
This is my code and when am trying to run this in browser i got message "The requested resource is not available." 这是我的代码,当尝试在浏览器中运行此代码时,出现消息“请求的资源不可用”。 Please anyone tell me what i have done wrong ?Thanks
请有人告诉我我做错了吗?谢谢
A correction is required in dispatcher-servlet.xml. 在dispatcher-servlet.xml中需要更正。 Instead of using suffix as 'index.jsp' it should be '.jsp'.
不应将后缀用作“ index.jsp”,而应使用“ .jsp”。 Second you should also point to the view type for example JSTLView.
其次,您还应该指向视图类型,例如JSTLView。 Here is a snapshot for your reference:
这是快照供您参考:
<bean id="viewResolver"
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="viewClass"
value="org.springframework.web.servlet.view.JstlView" />
<property name="prefix" value="/WEB-INF/view/" />
<property name="suffix" value=".jsp" />
</bean>
I am assuming that your controller class is in package 'com.helloworld' and you are hitting a URL similar to hostname:port/AppName/hello Where AppName is your Application Name, hostname could be localhost and port be default is 8080. 我假设您的控制器类位于包'com.helloworld'中,并且您命中类似于URL的主机名:port / AppName / hello其中AppName是您的应用程序名称,主机名可以是localhost,端口默认是8080。
Change your index.jsp as 将index.jsp更改为
<body>
<center>
<h2>Hello World</h2>
<h3>
<a href="hello?name=ABC">Click Here</a>
</h3>
</center>
</body>
modify dispatcher-servlet as 将dispatcher-servlet修改为
<bean
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix">
<value>/WEB-INF/views/</value>
</property>
<property name="suffix">
<value>.jsp</value>
</property>
</bean>
Spring will resolve the view's name /hello as Spring会将视图的名称/ hello解析为
When request for /hello comes to controller it will redirect to helloworld.jsp.
prefix + view name + suffix = /WEB-INF/pages/helloworld.jsp
I hope this solves your problem. 我希望这能解决您的问题。
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