MySQL按两列排序

Question

I have a table like this: 我有一张这样的桌子：

id     |date        |publisher
1       2014-11-07   100
2       2014-11-07   0
3       2014-11-07   100
4       2014-11-06   0
5       2014-11-06   100
6       2014-11-05   100
7       2014-11-05   0
8       2014-11-05   0
9       2014-11-05   100

I am trying to get a result like this : 我试图得到这样的结果：

1       2014-11-07   100
3       2014-11-07   100
2       2014-11-07   0
4       2014-11-06   100   
5       2014-11-06   0
6       2014-11-05   100
9       2014-11-05   100
8       2014-11-05   0
7       2014-11-05   100

SO I am trying to sort the data in table by publish date and allways keep the publisher values on top for each day I got this so far: 因此，我试图按发布日期对表中的数据进行排序，并始终将发布者的价值保持在到目前为止的每一天：

select * from articles 
order by publisher DESC, date DESC

I get this result: 我得到这个结果：

1       2014-11-07   100
3       2014-11-07   100
5       2014-11-06   100
6       2014-11-05   100
9       2014-11-05   100
2       2014-11-07   0
4       2014-11-06   0
7       2014-11-05   0
8       2014-11-05   0

Which is wrong.... 哪有错...

Answer 1

You must invert the order of order by field, like this: 您必须按字段反转订单顺序，如下所示：

select * from articles 
order by date DESC, publisher DESC

The ORDER BY clause take care about order of field. ORDER BY子句负责字段的顺序。 In this query we tell: order by date in desc order and if two or more dates are equals, apply a further order on publisher in desc order. 在此查询中，我们说：按日期顺序按desc顺序排序，如果两个或多个日期相等，则按desc顺序对发布者应用另一个顺序。

EDIT As I promised, go to Sql Fiddle 编辑，如我所愿，请转到Sql Fiddle

MySQL按两列排序

问题描述

1 个解决方案

解决方案1
1 2014-11-13 15:40:19

MySQL按两列排序

问题描述

1 个解决方案

解决方案1 1 2014-11-13 15:40:19

解决方案1
1 2014-11-13 15:40:19