[英]Ajax loaded comment not working
My php file loops out each blog post in my database and also creates the comments section. 我的php文件循环出数据库中的每个博客文章,并创建注释部分。 The blogs post great.
博客发布很棒。 When I comment on the most recent blog post, the comment does not appear but it seems to add a line as the space expands, just does not include the comment.
当我评论最新的博客文章时,该评论未出现,但随着空间的扩大似乎添加了一行,只是不包括该评论。 When I comment on the first post, it works great and exactly as expected.
当我对第一篇文章发表评论时,它的效果很好,而且完全符合预期。 I can't figure out how to correct it.
我不知道如何纠正它。 I thought it was a matter of add a .closest to the comment-block selector but that didn't seem to do the trick.
我认为这是在注释块选择器中添加.closest的问题,但这似乎并没有解决问题。
I appreciate any help or feedback! 感谢您的帮助或反馈!
PHP/HTML PHP / HTML
<?php // retrive post
include('php/config.php');
include ('php/function.php');
dbConnect();
$blog_query = mysql_query(
'SELECT *
FROM Blog
ORDER BY DATE DESC');
$date = date_create($row['DATE']);
while($row = mysql_fetch_array($blog_query)): ?>
<div class="post">
<h2><?php echo $row['TITLE']?></h2>
<h3><?php echo date_format($date, 'l, F j, Y')?></h3>
<p><?php echo $row['CONTENT']?></p>
</div>
<h2>Comments.....</h2>
<div class="comment-block">
<?php // retrieve comments with post id
$comment_query = mysql_query(
"SELECT *
FROM Comments
WHERE BID = {$row['ID']}
ORDER BY CID DESC
LIMIT 15") or die(mysql_error());
while($comment = mysql_fetch_array($comment_query)):?>
<div class="comment-item">
<div class="comment-post">
<h3><?php echo $comment['UNAME'] ?> <span>said....</span></h3>
<p><?php echo $comment['COMMENT']?></p>
</div>
</div>
<?php endwhile?>
</div>
<h2>Submit new comment</h2>
<!--comment form -->
<form id="form" method="post">
<div>
<input type="hidden" name="BID" value="<?php echo $row['ID']?>">
<label> <span>Display Name: *</span>
<input id="uname" type="text" tabindex="1" name="commentName" required />
</label>
</div>
<div>
<label> <span>Comment: *</span>
<textarea id="textarea" placeholder="Enter your comment here..." tabindex="2" name="commentMessage" required></textarea>
</label>
</div>
<div>
<input type="submit" id="submit" value="Submit Comment">
</div>
</form>
<?php endwhile?>
</div>
Jquery/Ajax: jQuery的/阿贾克斯:
var form = $('form');
var submit = $('#submit');
form.on('submit', function(e) {
// prevent default action
e.preventDefault();
// send ajax request
$.ajax({
url: 'php/ajaxcomment.php',
type: 'POST',
cache: false,
data: form.serialize(), //form serizlize data
beforeSend: function(){
// change submit button value text and disabled it
submit.val('Submitting...').attr('disabled', 'disabled');
},
success: function(data){
// Append with fadeIn see http://stackoverflow.com/a/978731
var item = $(data).hide().fadeIn(800);
$('.comment-block').append(item);
// reset form and button
form.trigger('reset');
submit.val('Submit Comment').removeAttr('disabled');
},
error: function(e){
alert(e);
}
});
});
ajajcomment.php ajajcomment.php
<?php
if (isset( $_SERVER['HTTP_X_REQUESTED_WITH'] )):
include('config.php');
include('function.php');
dbConnect();
if (!empty($_POST['commentName']) AND !empty($_POST['commentMessage']) AND !empty($_POST ['BID'])) {
$name = mysql_real_escape_string($_POST['commentName']);
$comment = mysql_real_escape_string($_POST['commentMessage']);
$BID = mysql_real_escape_string($_POST['BID']);
mysql_query("
INSERT INTO Comments
(UNAME, BID, COMMENT)
VALUES('{$name}', '{$BID}', '{$comment}')");
}
?>
<div class="comment-item">
<div class="comment-post">
<h3><?php echo $name ?> <span>said....</span></h3>
<p><?php echo $comment ?></p>
</div>
</div>
<?php
dbConnect(0);
endif?>
What does "php/ajaxcomment.php" return when you post a comment? 发表评论后,“ php / ajaxcomment.php”返回什么? Pure HTML?
纯HTML?
I'd make the "php/ajaxcomment.php" return JSON, for example: 我将使“ php / ajaxcomment.php”返回JSON,例如:
<?php
/*
here you do what ever you do now,
Insert the new comment to database, etc
*/
// Then you return the inserted data:
$data = array(
'UNAME' => $username,
'COMMENT' => $comment,
);
header('Content-Type: application/json');
print json_encode( $data );
?>
..and change the ajax: ..并更改ajax:
...
...
success: function(data){
var commentItem = $('<div/>').addClass('comment-item');
var commentPost = $('<div/>').addClass('comment-post');
var user = $('<h3/>').html( data.UNAME +'<span>said...</span>' );
var comment = $('<p/>').html( data.COMMENT );
commentItem.html( commentPost.html( user + comment ) ).hide().fadeIn(800);
$('.comment-block').append(commentItem);
// reset form and button
form.trigger('reset');
submit.val('Submit Comment').removeAttr('disabled');
},
...
...
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