在Linux中使用信号处理程序

Question

void f(int);
void main()
{
    signal(SIGINT, f);
    int i = 4;
    while(i < 1000)
    {
       sleep(10);
        i++;
     }
}

void f( int signum ){
    printf ( "OUCH \n") ;
}

if I hit "ctr C" while the program is looping, it prints out "OUCH" to the terminal. Is there anyway I can print out the current number that the program is looping using signal handler.

Answer 1

You can use global variables to store the value of the loop variable. You can then access this variable from the signal handler. Although you need to be very careful while doing this.

Please go through: Providing/passing argument to signal handler

Answer 2

Yes you can just add a static variable and keep the value in it in each iteration.

void f(int);
static int temp=0;
void main()
{

    int i = 4;
    while(i < 1000)
    {
       sleep(10);
        i++;
        temp=i;
     }
}

void f( int signum ){
    printf ( "OUCH %d \n", temp) ;


}