PHP MySQL日期大于

Question

Ok...

So I have a string which in this case checks the date with the PHP date('Ymd H:i:s'); I want this to check with a database row, if it's larger than.

$sql="SELECT * FROM date WHERE '$this->dateClose' < start_time AND '$this->dateOpen' < end_time";

It's in a loop so it will print everything which has a start_time less than dateClose and the opposite for dateOpen and end_time. But it doesn't work, please help.

Answer 1

尝试使用WHERE field operator value_to_match并以正确的格式更改值以匹配datetime

$sql="SELECT * FROM date WHERE start_time > '".date('Y-m-d H:i:s', strtotime($this->dateClose))."' AND end_time < '".date('Y-m-d H:i:s', strtotime($this->dateOpen))."'";

Answer 2

请尝试这个

$sql="SELECT * FROM date WHERE '".$this->dateClose."' < start_time AND '".$this->dateOpen."' < end_time";

Answer 3

For the given values

start_time = 2014-11-01 21:00 end_time = 2014-11-02 19:00 
$this->dateOpen = 2014-11-01 20:00 $this->dateClose = 2014-11-02 18:00

geting no rows from sql is OK. There is no valid row for your condition

WHERE '2014-11-02 18:00' < start_time AND '2014-11-01 20:00' < end_time'

the '2014-11-02 18:00' < '2014-11-01 21:00' part is false. You have to rethink what you want to get from your sql.