[英]Best way to sort list with index array
I would like to sort a list of strings with an array of integers as the new indexes: 我想用整数数组对字符串列表进行排序作为新索引:
Integer[] newIndexes = {0,2,1};
List<String> fruits = new ArrayList<>();
fruits.add("Apple");
fruits.add("Pear");
fruits.add("Banana");
fruits.sort....
What would be the best way to do this? 最好的方法是什么?
Using Java 8, you can do it using a stream of the indexes and the map()
method: 使用Java 8,您可以使用索引流和map()
方法来实现:
List<String> sortedFruits = Stream.of(newIndexes).map(fruits::get).collect(Collectors.toList());
gives the list 给出清单
[Apple, Banana, Pear]
You can use a SortedMap
to map the integers to the string values. 您可以使用SortedMap
将整数映射到字符串值。 This way it will sort the string values according to the natural ordering of the keys: 这样,它将根据键的自然顺序对字符串值进行排序:
SortedMap<Integer, String> map = new TreeMap<Integer, String>();
for (int i = 0; i < newIndexes.length; i++) {
map.put(newIndexes[i], fruits.get(i));
}
Collection<String> sortedFruits = map.values();
If you intend to sort the strings alphabetically, then you can just use Collections#sort()
. 如果您打算按字母顺序对字符串进行排序,则可以使用Collections#sort()
。
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