[英]Java LinkedList removing the last node
I have a Java class which consists of a node list, WordNode
, which has the attributes of the class Word
and a WordNode object called next
used as reference to the next node, as follows: 我有一个Java类,它由节点列表
WordNode
组成,该节点列表具有Word
类的属性和一个称为next
的WordNode对象,该对象用作对下一个节点的引用,如下所示:
class WordNode
{
Word word;
WordNode next;
WordNode(Word w)
{
word = w;
next = null;
}
Word getWord()
{
return word;
}
}
And the class Word
has a String called name
: Word
类有一个名为name
的字符串:
class Word
{
String name;
Word(String n)
{
this.name = n;
}
public String getName()
{
return name;
}
public void setName(String n)
{
name = n;
}
}
I have a class which is a custom LinkedList to which I must add and remove words by specifying the word name. 我有一个类,它是一个自定义LinkedList,必须通过指定单词名称在其中添加和删除单词。 I am able to add without problems, but when I want to delete I have some issues.
我能够添加而不会出现问题,但是当我要删除时会遇到一些问题。 Below is the method to delete:
以下是删除方法:
boolean remove(Word w)
{
WordNode wm = new WordNode(w);
if (list == null) return false; //can't delete on an empty list
else
{
WordNode aux = list;
while(aux != null)
{
if (wm.word.getName().compareTo(aux.word.getName()) == 0 ) //if the word to delete is found
{
if (aux.next == null) //to erase the last element
{
aux = null;
}
else
{
aux.word.setName(aux.next.word.getName()); //set current node's name to equal next node's
WordNode temp = aux.next.next;
aux.next = null; //to erase current node
aux.next = temp; //re-refer
}
return true;
}
else aux = aux.next;
}
return false; //reachable if word is not found
}
}
Where list
is supposed to be the LinkedList that holds all the nodes. list
应该是包含所有节点的LinkedList。 aux
is an auxiliary list that will cycle through the list
to avoid un-linking. aux
是一个辅助列表,它将在list
循环显示,以避免取消链接。 So, if I choose to remove a WordNode I compare names. 因此,如果我选择删除WordNode,则会比较名称。 It is actually removing well when the node is at any place, except the last node:
实际上,当节点位于除最后一个节点之外的任何位置时,它的移除效果很好:
if (aux.next == null) //to erase the last element
{
aux = null;
}
I'm hoping to make that node null to mark a new end to the list, but it doesn't get erased. 我希望将该节点设置为null,以将列表标记为新的结尾,但不会被擦除。 What could I change to erase the last element?
我可以更改哪些内容来擦除最后一个元素? Thank you for any help/suggestions in advance
感谢您的任何帮助/建议
You have to clear the WordNode's "next" pointer. 您必须清除WordNode的“下一个”指针。 As you don't have a "previous" pointer, you have to keep track of the previous WordNode manually.
由于没有“上一个”指针,因此必须手动跟踪上一个WordNode。
boolean remove(Word w)
{
WordNode wm = new WordNode(w);
if (list == null) return false; //can't delete on an empty list
else
{
WordNode aux = list;
WordNode prev = aux;
while(aux != null)
{
if (wm.word.getName().compareTo(aux.word.getName()) == 0 ) //if the word to delete is found
{
if (aux.next == null) //to erase the last element
{
prev.next = null;
// Takes care of the case of a one-item list
aux = null;
}
else
{
aux.word.setName(aux.next.word.getName()); //set current node's name to equal next node's
WordNode temp = aux.next.next;
aux.next = null; //to erase current node
aux.next = temp; //re-refer
}
return true;
}
else {
prev = aux;
aux = aux.next;
}
return false; //reachable if word is not found
}
}
Add a head
node. 添加
head
节点。 Then in your check for last node you will have: 然后,在检查最后一个节点时,您将拥有:
if (aux.next == null) //to erase the last element
{
aux.head.next = null;
}
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