在调用函数和定义的函数中传递与参数相同的id

Question

I have a select menu . On selecting the values it triggers getvalyear() function passing selected option as parameter. I need to call the getvalue() function inside display() function with same parameter described earlier. I also have to pass the argument to display() function.

Any helps are recommended.

Code snip of my description is described below.

   <select name="year" id="year"  style="width: 200px" onchange="getvalue(this)">
              <option>--Select Year--</option>
              <option value="2014">2014</option>
              <option value="2015">2015</option>
              <option value="2016">2016</option>
              <option value="2017">2017</option>   
              <option value="2018">2018</option>
    </select>



<script type="text/javascript">

 function getvalue(ctrl1){

      var sel = ctrl1.selectedIndex; 
      var selVal1 = ctrl1.options[sel].value; 

    }

function display(clicked_id)
{
    getvalyear(id);
}

</script>

Answer 1

If I understood the problem, you can try this code to display select boxes manually:

function display(clicked_id) {
    getvalue($('#' + clicked_id)[0]);
}

// select year
display('year');