如何在红宝石中将斜杠（/）换成“”

Question

To gsub / to "" ruby

I tried as,

ss = "http://url.com/?code=\#{code}"

I am fetching this url from database then have to gsub \\ to '' to pass the dynamic value in code

How to gsub \\ to ''

required output

ss = "http://url.com/?code=#{code}"

Answer 1

Your problem is actually not a problem. When you write "http://url.com/?code=\\#{code}" in ruby, \\# means that ruby is escaping the # character, cause # is a protected character. So you should have the backslash to escape it.

Just to prove this, if you write in a console your string with single quotes (single quotes will escape any special character (but single quotes, of course)):

>> 'http://url.com/?code=#{code}'
=> "http://url.com/?code=\#{code}"

This may be a little obscure but, if you want to evaluate the parameter code in the string, you could do something like this:

>> code = 'my_code'
>> eval("\"http://url.com/?code=\#{code}\"")
=> "http://url.com/?code=my_code"

Answer 2

I believe what you may be asking is "how do I force Ruby to evaluate string interpolation when the interpolation pattern has been escaped?" In that case, you can do this:

eval("\"#{ss}\"")

If this is what you are attempting to do, though, I would highly discourage you. You should not store strings containing the literal characters #{ } in your database fields. Instead, use %s and then sprintf the values into them:

# Stored db value
ss = "http://url.com/?code=%s"

# Replace `%s` with value of `code` variable
result = sprintf(ss, code)

If you only need to know how to remove \\ from your string, though, you can represent a \\ in a String or Regexp literal by escaping it with another \\ .

ss.gsub(/\\/,'')