成功提交JQuery表单$ .post（）处理显示消息

Question

I have a form I am submitting with $.post() in jquery..

$.post("testpage.php", $("#payment-form").serialize())

The post works fine itself, but when the post is done and successful the page will do other stuff such as display a thank you message and stuff. I just need to where to put to call to display the message.I do not understand where it goes in terms of the success being returned from the post.

Answer 1

You can specify a 3rd argument to .post() that is the "success" callback. It is a function to call when the .post execution is successful.

$.post("testpage.php", $("#payment-form").serialize(), function() { alert('post was successful!')})

Source: http://api.jquery.com/jquery.post/

Answer 2

In short, like this:

$.post("testpage.php", $("#payment-form").serialize(), function () {
    // Start partying here.
}).fail(function() {
    // Handle the bad news here.
})

Answer 3

Alternatively, you can use deferred objects , like as follow:

// Create POST request
var paymentPost = $.post("testpage.php", $("#payment-form").serialize());

// Assigned deferred objects
// "data" refers to the data, preferably in JSON format, returned by testpage.php
paymentPost
.done(function(data) {
    // Success
    // e.g. display thank you message, redirect to a payment successful page...
})
.fail(function(data) {
    // If error
    // e.g. display error message(s)
})
.always(function() {
    // Will always fire as long as POST request is submitted and completed
});

p/s: It is important to note that jqXHR methods like .success() and .error() are deprecated. To prepare for their eventual removal, you should abide to the new nomenclature for deferred objects ;)