foo（{0，0}）：这是否使用初始化列表？

Question

How does this code allow calling foo without naming the Vec type at the construction site? Is this syntax a case of C++11 initializer lists?

struct Vec {
    Vec(int x, int y) {
    }
};
void foo(Vec) {
}
int main() {
    foo({0, 0}); // normally I'd pass Vec(0, 0) or Vec{0, 0}
}

I'm sure this is a duplicate question but I don't know what to search for.

Answer 1

As stated by Piotr S., this is copy list initialization . The braced-init-list is used to initialize the function parameter. In copy-list-initialization, only non-explicit constructors are considered. This means that if Vec::Vec(int, int) was explicit, {0, 0} would cause a compiler error and Vec{0, 0} would be required.