如果条件不适用于网址匹配，则为PHP

Question

I am trying to match two URLs but it seems doesn't work. I have tried works fine if I put manually.

Here is the code:

$referby = $_SERVER['HTTP_REFERER'];
$link1="http://domain.com/admin/ajax/passcodev.php?order_id=".$orderid;
$link2="http://www.domain.com/admin/ajax/passcodev.php?order_id=".$orderid;

if($referby<>$link1 || $referby<>$link2)
 {
    header('Location:passcodev.php?order_id='.$orderid);
 }

I have no idea where I am doing mistake.

Answer 1

if($referby<>$link1 || $referby<>$link2) means if $referby does not match $link1 or $link2 , proceed. Since it can't match both it always evaluates to true.

You need to use && (and):

if($referby != $link1 && $referby != $link2)