查找列表的最小值、最大值和平均值

Question

I am having hard time to figure out how to find min from a list for example

somelist = [1,12,2,53,23,6,17]

how can I find min and max of this list with defining ( def ) a function

I do not want to use built-in function min

Answer 1

from __future__ import division

somelist =  [1,12,2,53,23,6,17] 
max_value = max(somelist)
min_value = min(somelist)
avg_value = 0 if len(somelist) == 0 else sum(somelist)/len(somelist)

If you want to manually find the minimum as a function:

somelist =  [1,12,2,53,23,6,17] 

def my_min_function(somelist):
    min_value = None
    for value in somelist:
        if not min_value:
            min_value = value
        elif value < min_value:
            min_value = value
    return min_value

Python 3.4 introduced the statistics package, which provides mean and additional stats:

from statistics import mean, median

somelist =  [1,12,2,53,23,6,17]
avg_value = mean(somelist)
median_value = median(somelist)

Answer 2

Return min and max value in tuple:

def side_values(num_list):
    results_list = sorted(num_list)
    return results_list[0], results_list[-1]


somelist = side_values([1,12,2,53,23,6,17])
print(somelist)

Answer 3

Only a teacher would ask you to do something silly like this. You could provide an expected answer. Or a unique solution, while the rest of the class will be (yawn) the same...

from operator import lt, gt
def ultimate (l,op,c=1,u=0):
    try:
        if op(l[c],l[u]): 
            u = c
        c += 1
        return ultimate(l,op,c,u)
    except IndexError:
        return l[u]
def minimum (l):
    return ultimate(l,lt)
def maximum (l):
    return ultimate(l,gt)

The solution is simple. Use this to set yourself apart from obvious choices.

Answer 4

list=[]
n = int(input("Enter the length of your list: "))
for i in range (1,n+1):
    a=int(input("Enter the %d number: " %i ))
    list.append(a)
min=list[0]
max=list[0]
for i in range(1,n):
    if max<list[i]:
        max=list[i]
    if min>list[i]:
        min=list[i]
print(" %d is the biggest number " %max)
print(" %d is the smallest number " %min)

Answer 5

Given your list : somelist = [1,12,2,53,23,6,17] First, make it a DataFrame using Pandas.
Then you can use the describe() method on the DF. Code:

import pandas as pd
somelist = [1,12,2,53,23,6,17]
somelist_df = pd.DataFrame(somelist)
somelist_df.describe()

OUTPUT:

count   7.000000
mean    16.285714
std 18.052833
min 1.000000
25% 4.000000
50% 12.000000
75% 20.000000
max 53.000000