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工作日SQL查询

[英]Working days SQL query

I have a problem I can't get my head around. 我有一个问题,我无法解决。

I have a table of events and a table of users. 我有一个事件表和一个用户表。 Some events are chargeable and some are not. 有些事件收费,有些则不收费。 What I want to establish is the number chargeable days per week month and year for every user. 我要确定的是每个用户每个月每个月要收取的天数。

Here is the data... 这是数据...

ID FromDate    ToDate       isChargeable     Username
1  2014-11-03  2014-11-04        Y           AUser 
2  2014-11-04  2014-11-06        Y           AUser
3  2014-11-07  2014-11-07        Y           AUser

And I've written a basic query to calculate the difference between the from and to dates and sum them adding 1 to the total as the toDate counts as a full day. 而且我编写了一个基本查询来计算起始日期和截止日期之间的差异,并对它们进行求和,然后将总计加1,以将toDate视为一整天。

SELECT DISTINCT FromDate, ToDate, isChargeable,Username, DATEDIFF(day, FromDate, ToDate) + 1) AS 'count1'
FROM            dbo.vDiary
GROUP BY FromDate, ToDate, isChargeable,Username

This results in... 这导致...

      FromDate    ToDate       isChargeable     Username   count1
      2014-11-03  2014-11-04        Y           AUser      2
      2014-11-04  2014-11-06        Y           AUser      3
      2014-11-07  2014-11-07        Y           AUser      1

Which is incorrect as it's showing 6 working days because two events are overlapping. 这是不正确的,因为它显示6个工作日,因为两个事件重叠。

How can I allow for this overlapping? 如何允许这种重叠? I need to state that if there is an event on a particular day that is chargeable then that day is a chargeable day. 我需要声明,如果某个特定日期有活动需要收费,那么该天就是应收费的日子。

I think I need a calendar table but I'm not sure on the process of using it to get the right results. 我认为我需要一个日历表,但是我不确定使用它来获取正确结果的过程。

Any help would be really appreciated!! 任何帮助将非常感激!!

Thanks 谢谢

Steve 史蒂夫

EDIT: Trying solution from below 编辑:从下面尝试解决方案

        ;WITH cte
     AS (SELECT Row_number()OVER(PARTITION BY Username ORDER BY FromDate) rn,
                FromDate,ToDate,isChargeable,Username
         FROM   #calen)
SELECT a.FromDate,a.ToDate,a.isChargeable,a.Username,
       CASE
         WHEN a.FromDate > b.ToDate
               OR b.ToDate IS NULL THEN Datediff(day, a.FromDate, a.ToDate) + 1
         ELSE Datediff(day, Dateadd(dd, 1, b.ToDate), a.ToDate)+ 1
       END DatDiff,
       *
FROM   cte a
       LEFT JOIN cte b
              ON a.rn = b.rn + 1
                 AND a.username = b.username
WHERE  ( a.ToDate > b.todate
          OR b.ToDate IS NULL ) 

Produces (updated) 产生(更新)

FromDate    ToDate  isChargeable    Username    DatDiff rn  FromDate    ToDate  isChargeable    Username    rn  FromDate    ToDate  isChargeable    Username
2014-11-03  2014-11-04  Y   AUser                2      1   2014-11-03  2014-11-04  Y   AUser   NULL    NULL    NULL    NULL    NULL
2014-11-04  2014-11-06  Y   AUser                2      2   2014-11-04  2014-11-06  Y   AUser   1   2014-11-03  2014-11-04  Y   AUser
2014-11-07  2014-11-07  Y   AUser                1      3   2014-11-07  2014-11-07  Y   AUser   2   2014-11-04  2014-11-06  Y   AUser
2014-12-03  2014-12-15  Y   AUser                13     4   2014-12-03  2014-12-15  Y   AUser   3   2014-11-07  2014-11-07  Y   AUser
2014-12-10  2014-12-17  Y   AUser                2      5   2014-12-10  2014-12-17  Y   AUser   4   2014-12-03  2014-12-15  Y   AUser
2015-12-04  2015-12-15  Y   AUser                12     6   2015-12-04  2015-12-15  Y   AUser   5   2014-12-10  2014-12-17  Y   AUser
2014-11-03  2014-11-03  Y   BUser                1      1   2014-11-03  2014-11-03  Y   BUser   NULL    NULL    NULL    NULL    NULL
2014-11-04  2014-11-04  Y   BUser                1      2   2014-11-04  2014-11-04  Y   BUser   1   2014-11-03  2014-11-03  Y   BUser

Try this. 尝试这个。

If you have Unique ID's try this. 如果您有唯一ID,请尝试此操作。

create table #calen(ID int, FromDate   date, ToDate date,isChargeable char(1),Username varchar(20))

INSERT #calen
VALUES (1,'2014-11-03','2014-11-04','Y ','AUser'),
       (2,'2014-11-04','2014-11-06','Y','AUser'),
       (3,'2014-11-07','2014-11-07','Y','AUser') 


SELECT a.FromDate,a.ToDate,a.isChargeable,a.Username,
       CASE
         WHEN a.FromDate > b.ToDate
               OR b.ToDate IS NULL THEN Datediff(day, a.FromDate, a.ToDate) + 1
         ELSE Datediff(day, Dateadd(dd, 1, b.ToDate), a.ToDate)
              + 1
       END DatDiff
FROM   #calen a
       LEFT JOIN #calen b
              ON a.id = b.id + 1
WHERE  ( a.ToDate > b.todate
          OR b.ToDate IS NULL ) 

Update : 更新:

For more than one user. 对于多个用户。

;WITH cte
     AS (SELECT Row_number()OVER(PARTITION BY Username ORDER BY FromDate) rn,
                FromDate,ToDate,isChargeable,Username
         FROM   #calen)
SELECT a.FromDate,a.ToDate,a.isChargeable,a.Username,
       CASE
         WHEN a.FromDate > b.ToDate
               OR b.ToDate IS NULL THEN Datediff(day, a.FromDate, a.ToDate) + 1
         ELSE Datediff(day, Dateadd(dd, 1, b.ToDate), a.ToDate)+ 1
       END DatDiff
FROM   cte a
       LEFT JOIN cte b
              ON a.rn = b.rn + 1
                 AND a.username = b.username
WHERE  ( a.ToDate > b.todate
          OR b.ToDate IS NULL ) 

OUTPUT : 输出:

FromDate    ToDate      isChargeable    Username    DatDiff
----------  ----------  ------------    --------    -------
2014-11-03  2014-11-04  Y               AUser           2
2014-11-04  2014-11-06  Y               AUser           2
2014-11-07  2014-11-07  Y               AUser           1

If all the ID values are not unique we can have the below query: 如果所有ID值都不都是唯一的,我们可以进行以下查询:

SELECT ID, FromDate, ToDate, isChargeable, Username,
 CASE WHEN EXISTS(SELECT ToDate FROM UserTable B WHERE A.FromDate = B.ToDate 
   AND A.UserName = B.UserName AND A.ID <> B.ID) THEN
   DATEDIFF(day, FromDate, ToDate)
 ELSE
   DATEDIFF(day, FromDate, ToDate) + 1
 END  AS 'count1'
FROM UserTable A

else we have to create CTE to create unique ROWID. 否则,我们必须创建CTE才能创建唯一的ROWID。

;WITH UserTable
     AS (SELECT Row_number() OVER(ORDER BY FromDate) RowID,
                FromDate,ToDate, isChargeable, Username
         FROM #user)

SELECT RowID, FromDate, ToDate, isChargeable, Username,
 CASE WHEN EXISTS(SELECT ToDate FROM UserTable B WHERE A.FromDate = B.ToDate 
       AND A.UserName = B.UserName AND A.RowID <> B.RowID) THEN
   DATEDIFF(day, FromDate, ToDate)
 ELSE
   DATEDIFF(day, FromDate, ToDate) + 1
 END  AS 'count1'
FROM UserTable A

try this : 尝试这个 :

WITH CTE AS 
(SELECT a.* ,y.flag
FROM EventsTable a
OUTER APPLY 
  (SELECT DATEDIFF(dd, a.ToDate, x.FromDate) as flag 
  FROM EventsTable x 
  WHERE a.id = x.id AND x.FromDate > a.ToDate) y)

SELECT id,FromDate,ToDate,isChargeable,Username,
   CASE WHEN flag = 1 THEN 
      DATEDIFF(dd, FromDate, ToDate) 
   ELSE DATEDIFF(dd, FromDate,ToDate) + 1 
   END AS count1
FROM CTE

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