如何基于赢/亏损列在PHP中的Mysql查询中获取百分比

Question

I need this Rank query to also have an IF statement to calculate the wins/losses and put the percentage in a @percentage variable. I have no idea how to combine a rank query with a percentage query.

mysql_query("SELECT name, wins, losses, level, xp, @curRank := @curRank + 1 AS rank 
FROM teams p, (SELECT @curRank := 0) r 
WHERE `console` = 3 AND `game` = 23 AND `laddertype` = 1 
ORDER BY xp DESC");

Answer 1

选择名称，获胜，损失，级别，xp，获胜AS W，损失AS L，TRUNCATE（wins / IF（wins = 0,1，wins + loss）* 100,0）AS PCT，@curRank：= @curRank +队伍p的AS排名为1，（选择@curRank：= 0）r console = 3 AND game = 23 laddertype = 1 ORDER BY xp DESC；