文件中的awk和regexp

Question

I have a file:

first basket with apple
second basket with apricota
third basket with tomato
fourth basket with olives
fifth empty basket

I must print each word which contain in end /e,o,y/ letter in each 1,3,5.N string. Result must be: apple,tomato,empty. I can separate 1,3,5 string, but can not separate each word in string and check it

awk '{if (NR % 2 != 0); {if (/(y|e|o)$/) print $0}}' inputfile

and have in result

first basket with apple

Answer 1

You can use something like

$ awk 'NR % 2 { for (i=1; i<=NF; i++) if ($i  ~ /[eoy]$/) print $i}' input
apple
tomato
empty

What it does?

• NR % 2 selects the lines 1 3 5...

• if ($i ~ /[eoy]$/) checks if each field, wrod ends with a e or o or y

Answer 2

Seems like you want something like this,

$ awk '{for(i=1;i<=NF;i++){if($i ~ /.*(e|o|y)$/){print $0}}}' file
first basket with apple
third basket with tomato
fifth empty basket

To get the words only,

$ awk '{for(i=1;i<=NF;i++){if($i ~ /.*(e|o|y)$/){print $i}}}' file
apple
tomato
empty

Answer 3

Here is a gnu awk solution (due to multiple characters in RS ):

awk -v RS=" |\n" '/([yeo])$/' file
apple
tomato
empty

Here RS is set to space or newline, so it will run one and one word on each line.