使用sort方法和JOptionPane让用户输入10个数字，然后输出10个已排序的数字

Question

This is what I have so far:

import javax.swing.JOptionPane; public class Aukeemhw3 {

/**
 * 
 * @param numberSort the purpose is to sort 10 input numbers
 */

public static void numInputSort(int[] numberSort){

    for(int i = 0; i < (numberSort.length - 1); i++){

        int min = i;

                for(int j = i; j < (numberSort.length); j++){
                        if(numberSort[j] < numberSort[min])
                            min = j;
                }
                int temp = numberSort[min];
                numberSort[min] = numberSort[i];
                numberSort[i] = temp;
    }
}
/*
* @param args the command line arguments
*/
public static void main(String[] args) {
    // Request for user to enter 10 numbers

    String[] numbers;
    numbers = new String[10];

    JOptionPane.showInputDialog("Enter " + numbers + "Values: ");

    numImportSort(int[] numbers);


}

}

I keep getting errors with everything I try when calling my method at the last line. I can't figure out how to properly code my main argument to ask the user to input 10 numbers then call my sort method numInputSort to sort the 10 numbers being input.

Answer 1

Plenty of errors in the main method. What you should do to fix:

• JOptionPane returns String so you should enter your numbers so that it can be converted to numbers, with some sort of delimiter
• Split and convert to numbers
• Assemble and int array and call the method

Something like

public static void main(String[] args) {
    // Request for user to enter 10 numbers

    int[] numbers = new int[10];

    String sNumbers =  JOptionPane.showInputDialog("Enter number values, split with comma: ");

    String[] singleNumbers = sNumbers.split(",");
    for (int i = 0; i < singleNumbers.length; i++) {
        numbers[i] = Integer.parseInt(singleNumbers[i].trim());
    }
    numInputSort(numbers);
    JOptionPane.showMessageDialog(null, Arrays.toString(numbers), "sorted",  JOptionPane.INFORMATION_MESSAGE);
}