排序列包含数字和字母数字值时，SQL排序失败

Question

I'm attempting to sort by a field with may contain either numbers, or a letter followed by a number. (But not a mix of both).

My Sort ascending field is

 sField: IIf(Val([AlbumTrack]) > 0, CInt([AlbumTrack]), [AlbumTrack])

But numbers are not sorting correctly. Letter and numbers seem to be. What am I doing wrong ?

Examples of data are 7,8,9,10,11 A3, A4, A5, B1, B2, C1

My sql is

SELECT DISTINCTROW 
    CDTracks.AlbumCat, CDTracks.AlbumTrack, 
    IIf(Val([AlbumTrack])>0,CInt([AlbumTrack]),[AlbumTrack]) AS sField
FROM 
    CDTracks
WHERE 
    (((CDTracks.AlbumCat) = "RCA Victor LSP 2525"))
ORDER BY 
    IIf(Val([AlbumTrack]) > 0, CInt([AlbumTrack]), [AlbumTrack]);

Answer 1

Hmm, I see what you mean. The issue appears to be that the expression in your ORDER BY clause does not have a consistent data type: for some rows it evaluates to an Integer and for other rows it evaluates to a String.

The following worked for me because the expression in this ORDER BY clause always returns a String:

SELECT DISTINCTROW
    CDTracks.AlbumCat, CDTracks.AlbumTrack
FROM 
    CDTracks
WHERE 
    (((CDTracks.AlbumCat) = "RCA Victor LSP 2525"))
ORDER BY 
    IIf(Val([AlbumTrack]) > 0, Right("00000" & [AlbumTrack], 5), [AlbumTrack]);

Answer 2

If I understand your question correctly, this query shold return rows in the order that you want:

SELECT DISTINCTROW 
    CDTracks.AlbumCat, CDTracks.AlbumTrack
FROM 
    CDTracks
WHERE 
    CDTracks.AlbumCat = "RCA Victor LSP 2525"
ORDER BY
  IIf(Val([AlbumTrack]) > 0, Null, Left([AlbumTrack], 1)),
  IIf(Val([AlbumTrack]) > 0, CInt([AlbumTrack]), CInt(MID([AlbumTrack], 2)));

This will split the AlbumTrack column in two different columns: one for the alphanumeric part if present, one for the numeric part.