如何基于Java中的值从String获取垂直字符？

Question

Here i have String base="flames" and value will be dynamic.Based on values i need to get the character from base string.if value=0 i need to get output 'f' and if value more than 6 then i need to start 'f as 7' then print particular value.If value=10 then i need to get output as 'm'.Can anybody help me how to get this.This is my code.

public class demo {

public static void main(String[] args) {
    String base = "FLAMES";
    int value = 6;
    if (base.length() >= value) {
        System.out.println(value);
    }
 }
}

Your help will be appreciated.

Answer 1

Try mod operator:

int value = 6;
System.out.println(base.charAt(value % base.length()));//F
value = 7;
System.out.println(base.charAt(value % base.length()));//L

Remember You are saying 0 should give you F, so 10 would give you E and not M as below

FLAMESFLAMES
0 1 2 3 4 5 6 7 8 9 10 11

Answer 2

public static void main(String[] args) {
        String base = "FLAMES";
        int value = 1;
        value--;
        value = value % base.length();
        System.out.println(base.charAt(value));
     }

You can use modulus division in case the value is larger than the length of the string. This will give you the character for any input. Just add 1 to number I edited my post.

Answer 3

String - String is character array in java, and array always start with zero index.

F   L   A   M   E   S  
0   1   2   3   4   5

But, as per your question you need

    0 => F  
    7 => F  // String length is 6, but array index start from 0.
   10 => M

Modified Code : Here I have manged index if the value is greater then 7.

public class demo {

public static void main(String[] args) {
    String base = "FLAMES";
    int value = 10;  // get input 
    char c=base.charAt(value%base.length());  

    if(value>=7){ // if value exceeds the 6, 
        value = value-1;  // you have to do value-1 to manage index.
        c=base.charAt(value%base.length());
    }

    System.out.println("char : "+c);  // print result
 }