[英]python, remove words in a string from a list
I want to remove words in a string, which the words or 'seed' words in a list, 我想删除字符串中的单词,其中的单词或“种子”单词在列表中,
example: 例:
query = "LK936033.1 Babesia assembly 454hybrid_PBjelly scaffold Contig1323 7"
seeds = ["assembly","454","scaffold","contig"]
expect result: 预期结果:
"LK936033.1 Babesia 7"
I found a way to do remove words like this: 我找到了一种删除此类单词的方法:
' '.join([i for i in query.split() if i not in seeds])
but this method only removes the exact words from the seed list, but not the words containing the seeds. 但是此方法只会从种子列表中删除确切的单词,而不会删除包含种子的单词。
You'll need to expand your test; 您需要扩展测试; use the
any()
function for efficiency: 使用
any()
函数可提高效率:
' '.join([i for i in query.split() if not any(w in i.lower() for w in seeds)])
The any(w in i.lower() for w in seeds)
test uses a generator expression to test if the current word contains any of the seed words, lowercased; any(w in i.lower() for w in seeds)
测试使用生成器表达式来测试当前单词是否包含任何种子单词(小写); it'll only evaluate the minimum number of tests to find a match. 它只会评估找到匹配项的最少测试数量。
Demo: 演示:
>>> query = "LK936033.1 Babesia assembly 454hybrid_PBjelly scaffold Contig1323 7"
>>> seeds = ["assembly","454","scaffold","contig"]
>>> ' '.join([i for i in query.split() if not any(w in i.lower() for w in seeds)])
'LK936033.1 Babesia 7'
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