使用bash检查linux应用程序状态，并在不起作用时发出警报

Question

Hi guys the problem is pretty simple I just don't know how to solve this in bash. I want to write simple mule server status checker. I can check it using command:

./mule status

Then I receive to possible communicates:

If all ok:

MULE_HOME is set to /home/mule/mule
Mule is running (3496).

And if not ok:

MULE_HOME is set to /home/mule/mule
Mule is not running.

How can I catch this communicates and for example do simple if / else with - eq

Answer 1

The standard for that is using exitcodes, like all standard executable do. The program needs to use "exit" (without quotes) with some value. The receiver needs to evaluate "$?" (without quotes)