[英]Bash, selecting text surrounded by specific matches
What I need to do is print out the text which starts after the particular match and ends before another match. 我需要做的是打印出在特定比赛之后开始并在另一场比赛之前结束的文本。
Let's say I have a big output and I only need to print the text which starts after line '$$$$$$$$$$' and ends before line '((((((((('. Oh and the file might end without the '(((((((((' line, in which case I would still need that text after '$$$$$$$$$$' till the end of the output. 假设我有一个很大的输出,我只需要打印在'$$$$$$$$$$'行之后到'((((((((文件可能没有'((((((((((')line,在这种情况下,我仍然需要'$$$$$$$$$$$$'之后的文本,直到输出结束。
How would I do that? 我该怎么做?
You can use sed
: 您可以使用sed
:
sed -e '/\$\{10\}/,/(\{9\}/!d' inputfile
To exclude the boundary lines, you have to do some programming: 要排除边界线,您必须进行一些编程:
sed -ne '/\$\{10\}/ {n;b c}; d;:c {/(\{9\}/ {d};p;n;b c}' inputfile
You can use awk
你可以使用awk
awk '/START/{f=1;next} /END/{f=0} f' file
You can set start
stop
to what you like. 您可以将start
stop
设置为您喜欢的。
cat file 猫文件
test
$$$$$$$$$$
more
data
(((((((((
stop
awk '/\$\$\$\$\$\$\$\$\$\$/{f=1;next} /\(\(\(\(\(\(\(\(\(/{f=0} f' t
more
data
Since $
and (
is special characters, you need to escape them. 由于$
和(
是特殊字符,因此需要对其进行转义。
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