[英]use grep/sed/awk to extract string corresponding to certain field
On my Fedora system, I get the following: 在我的Fedora系统上,我得到以下信息:
$ cat /proc/net/arp
IP address HW type Flags HW address Mask Device
130.48.0.1 0x1 0x2 80:4b:c7:10:3e:41 * wlp1s0
How can I pipe the result of the Device (in this case the answer is wlp1s0) using a screen editor such as sed or grep or awk? 如何使用屏幕编辑器(例如sed或grep或awk)通过管道传输设备的结果(在这种情况下,答案为wlp1s0)?
Thanks! 谢谢!
$ awk '/^[0-9]/{print $6}' /proc/net/arp
wlp1s0
/^[0-9]/
selects lines that start with digit, ip /^[0-9]/
选择以ip开头的行
print $6
prints the 6th colum being the Device print $6
打印第六列作为设备
To get interface name used to get out of a computer, you can use this: 要获取用于退出计算机的接口名称,可以使用以下命令:
ip route get 8.8.8.8 | awk 'NR==1 {print $5}'
eth0
It will always get the correct, even if more than one inf is online. 即使在线有多个inf,它也始终会正确无误。
awk 'NR>1{print $6}' < /proc/net/arp
如果我们在第一行之后(以摆脱标题“ Device”),则打印第六个字段(由空格分隔)。
Assuming your fields are tab-separated, if the Device always appears as the last column: 如果设备始终显示为最后一列,则假定您的字段用制表符分隔:
$ awk -F'\t' 'NR>1{print $NF}' file
wlp1s0
otherwise: 除此以外:
$ awk -F'\t' 'NR==1{for (i=1;i<=NF;i++) f[$i]=i; next} {print $(f["Device"])}' file
wlp1s0
Four methods: 四种方法:
awk 'NR==1{for (i=1;i<=NF;i++) f[$i]=i; next} {print $(f["HW"])}' </proc/net/arp
awk 'NR==2{print $NF}' < /proc/net/arp
sed -nr '/^[0-9]/s#(.*)* (.*)#\2#gp' /proc/net/arp
sed -nr '/^[0-9]/s#(.*)\*[^a-z]*(.*)#\2#gp' /proc/net/arp
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