根据CPI，指令等计算程序的执行时间

Question

I'm trying to calculate the execution time of an application. Assuming the only stall penalty occurs on memory access instructions (100 cycles being the penalty). How am I supposed to find out execution time in seconds with this info?

CPI (CPUCycles?) = 1.0
ClockRate = 1GHZ
TotalInstructions = 59880
MemoryAccessInstructions = 8467
CacheMissRate = 62% (0.62) (5290/8467)
CacheHits = 3117
CacheMisses = 5290
CacheMissPenalty = 100 (cycles)

Assuming no other penalties.

Answer 1

totalCycles = TotalInstructions + CacheMisses * CacheMissPenalty ?

I assume that cache hits cost same as other opcodes, so those are included in TotalInstructions.

That's then 588880 cycles, 1GHz is 1000000000 cycles per second. So that code will take 0.58888ms to execute (5.8888e-7 second).

This value is of course purely theoretical estimate, as modern CPU doesn't work like that (1 instruction = 1 cycle). If you are interested in real world values, just profile it.