在函数内附加列表

Question

I am still a bit confused about how arguments are passed in python. I thought non-primitive types are passed by reference, but why does the following code not print [1] then?

def listTest(L):
    L = L + [1]


def main:
    l = []
    listTest(l)

    print l #prints []

and how could I make it work. I guess I need to pass "a pointer to L" by reference

Answer 1

In listTest() you are rebinding L to a new list object; L + [1] creates a new object that you then assign to L . This leaves the original list object that L referenced before untouched.

You need to manipulate the list object referenced by L directly by calling methods on it, such as list.append() :

def listTest(L):
    L.append(1)

or you could use list.extend() :

def listTest(L):
    L.extend([1])

or you could use in-place assignment, which gives mutable types the opportunity to alter the object in-place:

def listTest(L):
    L += [1]