C++ 异常 - 抛出一个字符串

Question

I'm having a small issue with my code. For some reason, when I try to throw a string with the code below, I get an error in Visual Studio.

#include <string>
#include <iostream>
using namespace std;

int main()
{
    
    char input;

    cout << "\n\nWould you like to input? (y/n): ";
    cin >> input;
    input = tolower(input);

    try
    {
        if (input != 'y')
        {
            throw ("exception ! error");
        }
    }
    catch (string e)
    {
        cout << e << endl;
    }
}

Error :

Answer 1

Throwing a string is really a bad idea.

Feel free to define a custom exception class, and have a string embedded inside (or just derive your custom exception class from std::runtime_error , pass an error message to the constructor, and use the what() method to get the error string at the catch-site), but do not throw a string!

Answer 2

you are currently throwing a const char* and not a std::string , instead you should be throwing string("error")

edit: the error is resolved with

throw string("exception ! error");

Answer 3

'''#include <string>
#include <iostream>
using namespace std;

int main()  
{
    
    char input;

    cout << "\n\nWould you like to input? (y/n): ";
    cin >> input;
    input = tolower(input);

    try
    {
        if (input != 'y')
        {
            throw std::runtime_error("Exception ! Error");
        }
    }

    catch(const std::exception& e)
    {
        std::cout << "Caught exception: " << e.what() << '\n';
    }
}'''